please help me and explain the answer. thanks

the position function of a particle moving in a horizontal line is s = 1/3t^3-3/2t^2+2t+1, where s feet is the directed distance of the particle from the origin at t seconds, t=0, a. find time/s when the particle momentarily stops. b. the position when the velocity is constant c. is total time of flight.

Question

please help me and explain the answer. thanks 

the position function of a particle moving in a horizontal line is s = 1/3t^3-3/2t^2+2t+1, where   s feet is the directed distance of the particle from the origin at t seconds, t>=0, a. find time/s when the particle momentarily stops. b. the position when the velocity is constant c. is total time of flight.

campbell_st · Answer

ok, the particle is stopped with it has no velocity

so find the 1st derivative and then set it equal to zero and solve for t.

anonymous · Answer

1t^2-3t+2

campbell_st · Answer

that's correct... so set it to zero and solve for t. 

only consider positive t values in the solution because of domain restrictions.

anonymous · Answer

i get, t=2,1