Question

@phi

Answer 1

What do you need help in?

Answer 2

calc:/

Answer 3

Oh haven't learned that yet.

Answer 4

to be continuous you need the two expressions be equal when x=3

Answer 5

so I would write down
3x+k= kx^2 - 6
and replace x with 3 to get
9 + k = 9k - 6

and solve for k

Answer 6

1.88 right?

Answer 7

8k= 15
k= 15/8
k= 1.875

to the nearest 100th,
k = 1.88

yes, you got it.

Answer 8

thanks!

Answer 9

one more question @phi

Answer 10

its the same type, and i got -2.47, did i do it right?

Answer 11

it does not look promising.

did you start with
3x+k= kx^2 - 5

and replace x with -4 ?
-12 + k = 16k - 5
now solve for k

Answer 12

-.47

Answer 13

thanks!

Answer 14

yes, that looks better