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integral of 2 cos (theta/2)??? I dont really get why it is 4sin(theta/2)...
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@mathstudent55
this is a standard integration \[\int\limits_{}^{}\cos(ax)dx=\frac{ 1 }{ a }\sin(ax)+c\]
wouldnt that be just sin(theta/2)? because the 1/2 cancels...
so.... \[\int\limits_{}^{}2 \cos(\frac{ \theta }{ 2 })d \theta=2\int\limits_{}^{}\cos \frac{ \theta }{ 2 }d \theta\\=2*\frac{ \sin \frac{ \theta }{ 2 } }{ 1/2 }+c\] ok?
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ok, i think that makes sense
yea, I think so
good :)
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