This is a few decently complex problems, anyone here able to help?!?! maybe help ? @satellite73 @TheLukeskywalker2 I will post pics of it below !!
I'll do my darnest to help.
Thank you !! Here it is --->
I have absolutly no idea how to do these -_- \(\color{blue}{\Huge\ddot\frown}\)
That I can help with. Give me a second to get my work down so I can start typing it in.
I have plenty of time. thank you !! \(\color{purple}{\Huge\ddot\smile}\)
get rid of the denominators and then its just a matter of mathing terms from one side to the other
You have a tricky math teacher. You'll see why once I finish. First, multiply the whole equation by 9 and by 5. The objective of this is to get rid of the denominators. Doing as such will give you \[35v+5w=-27v-72x\] Now we want to get everything with a v in it on one side, everything else on the other side. \[(35+27)v=62v=-5w-72x\] Now get v alone, which will leave you with \[v=\frac{ -5w-72x }{ 62 }\]. Therefore, the answer is none of the above. Hence what I said about your math teacher being tricky. Math teachers usually do not do that. Grab my attention if you need anything else explained.
Yea im homeschooled (online school) my math teacher gave us khan academy assignments, so khan academy makes th problems we have to work out... thank you and one quic question... what do you mean multiply the whole equation by 5 & 9 ?
multiply by the numerator instead of cross multiplying ?
@TheLukeskywalker2
When you multiply the whole equation by a certain number or value, you multiply both sides by it. The result is usually cross multiplying, but there are cases where you would want to multiply across without canceling something from a denominator.
ok thanks!!!
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