Question

The length of a rectangle is 8 in. more than its width. The perimeter is 52 in.

What is the length of the rectangle?

Answer 1

First you times 8 by 2 since there are two lengths or two sides equal to each other in a rectangle. then you would subtract 16 from 52 and get 36, now you would divide this by four because you already subtracted the extra length that makes it a triangle. You would get 9. 9 + 8 = 17 and that's your answer :)

Answer 2

let w be the width

Answer 3

since The length of a rectangle is 8 in. more than its width, we know

Answer 4

All 4 sides have to add to the perimeter 52, so

s1 + s2 + s3 + s4 = (w)+(w+8)+(w)+(w+8) = 4w+16 = 52


So you need to solve 4w + 16 = 52