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Another question, 2^(2x+7)=3^(x-13) in terms of logarithmic expression?
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take log of both sides use property \[\log(x^n) = n \log x\] then simply distribute, add like terms, factor out the x, divide :)
Steps after 2xlog(2)+7log(2)=xlog(3)-13log(3)?
combine the "x" terms on one side.... constants on other
then you will have to factor out the x to get it by itself
will -13log(3)-7log(2) become 13log(3)/7log(2) or -13log(3)/7log(2)?
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I know in this case it might not matter since it is being divided but for future reference.
hmm neither ... its just -13log(3) -7log(2)
Ahh thank you so much!
you may want to change the signs by multiplying everything by a negative
yw :)
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Noted! xD
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