Write an equation of the line containing the given point and parallel to the given line.
(2, -7); 5x-8y=7

Question

Write an equation of the line containing the given point and parallel to the given line.
(2, -7); 5x-8y=7

campbell_st · Answer

ok, what is the slope of the given line..?

anonymous · Answer

The slope is -5x/8

campbell_st · Answer

close
5x - 7 = 8y   so   y = 5/8 x - 7

so m = 5/8   and the point is (2, -7) 

an easy form of the line is 

y = mx + b

or 

$$y = \frac{5x}{8} + b$$

to find b, substitute the point, x = 2 and y = -7

hope it helps...

campbell_st · Answer

they you can re-write it in standard form...

anonymous · Answer

Thanks
Can you help me to write it in standard form?

campbell_st · Answer

ok... so what did you get for b?

anonymous · Answer

-7

campbell_st · Answer

not quite, if you substitute you get

$$-7 = \frac{5 \times 2}{8} + b$$

or 

$$-\frac{66}{8} = b$$
so in slope intercept form the equation is 

$$y = \frac{5}{8} x - \frac{66}{8}$$

now multiply every term by 8

$$8y = 5x - 66$$

so rewriting it in standard form 

5x - 8y = 66

campbell_st · Answer

lol... oops... just realised the easy method

if you let 

5x - 8y = b

then substitute x = 2 and y = -7

you get 

5x - 8y = 66

sorry, just a bit slow this morning

anonymous · Answer

Okay Thank you so much