. Write the equation of a line that passes through the point (-1, 2) with a slope of - 5 2 in slope-intercept. B. Graph the equation of the line.
the thing you attach is empty
First there is nothing on the attachment Second you should put it into point slope formula
ugh. idk how to attach the graph. sorry
Its okay
is the slope 5/2 or is it just 5?
it is -5/2
Alright the best way to do this is to start with Point Slope form do you know that?
no. honestly not sure of any thing with slopes
Its okay :)
the formula is y-y1=m(x-x1)
Do you know what your y1, m, and x1 are?
i wanna say the slope?
M is the slope and x1 and y1 are the x and ys of the point (-1,2)
so x1 and y1 repsent -5/2 ?
Now what would the formula look like?
No the -5/2 would represent the slope
the x1 would be the -1 and the y1 would be 2
okaayy lol i thinking i'm starting to understand. So, i may be wrong but what you're saying is x1 and y1 represent 2 ?
here let me explain a little more in depth okay?
okay. thank you, it's all very confusing.
the slope equation is y = mx + b where m is slope that you already have and b represent y -intercept and you have order pair which represent x and y
|dw:1412567902124:dw| plug this in to the equation and solve for b
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