Question

.23 and the 23 is repeating as a fraction would be...????

Answer 1

These can always be solved by the following method...

1) Determine the size of the sequence repeating numbers, "23" - That's 2
2) Raise 10 to that power. \(10^{2} = 100\)
3) Subtract 1: 100 - 1 = 99
4) Construct the repetitive digits divided by that value: 23/99

You are done.

Note: This works like this ONLY if the repetition starts immediately. It's a little different if there are some odd ducks up front, like 0.3334545454545... Those pesky '3's take a little more effort.

Answer 2

Thank you so much that really helped, I understand that no,you must do it by the number of digits are in the repeating bar and in the 1-0-0-0 0's of X.