Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

please help me find this arc length?

OpenStudy (anonymous):

The area of sector JLK in Circle L is 3pi in^2. Find m arcJK.

OpenStudy (anonymous):

|dw:1412715804884:dw|

OpenStudy (anonymous):

First find the angle using the formula (theta/2pi)*pi*r^2

OpenStudy (anonymous):

Idk what theta is.

OpenStudy (anonymous):

theta is the angle you have to find

OpenStudy (anonymous):

Since arc length is '(theta/2pi)*pi*r' :)

OpenStudy (anonymous):

Did you get it?

OpenStudy (anonymous):

I got 18

OpenStudy (anonymous):

@KissMyAxe

OpenStudy (anonymous):

18 what?

OpenStudy (anonymous):

The angle.

OpenStudy (anonymous):

exactly 18

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I think it is 0.52 radians

OpenStudy (anonymous):

I'm confused. Can you show me how to work it out? I understand better that way.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Do you know the final answer?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

So to find the angle it would be: (theta/2pi)*pi*r^2= 3pi in^2 on the LHS pi's cancel and we are left with: (theta/2)*r^2= 3pi in^2 let me know if you have any problem up till here

OpenStudy (anonymous):

Where did you get 3pi in^2?

OpenStudy (anonymous):

Well that's the are of sector, right?

OpenStudy (anonymous):

*area

OpenStudy (anonymous):

My book didn't have that in it. I couldn't find the word theta either. It must be a further lesson.

OpenStudy (anonymous):

I understand what you've done so far in the problem though.

OpenStudy (anonymous):

What are you going to rant about

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Its nothing!

OpenStudy (anonymous):

Well here in A-levels we call the the angle theta. What do you guys call it?

OpenStudy (anonymous):

.....All I was saying was the reason I didn't know what you were talking about was because my book didn't teach me it.

OpenStudy (anonymous):

I don't know why you spazzed..

OpenStudy (anonymous):

U were taking along time to answer :P

OpenStudy (anonymous):

Anyways we have to find the angle or theta

OpenStudy (anonymous):

Okay... I understand what you did so far in the problem.

OpenStudy (anonymous):

So angle= (2*3pi)/6^2

OpenStudy (anonymous):

Did you get this?

OpenStudy (anonymous):

Yes, .52

OpenStudy (anonymous):

Okay than we use the formula 'Arc length= r*angle' Since the angle is in radians this formula is a simplified one

OpenStudy (anonymous):

3.12?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Okay, thanks.

OpenStudy (anonymous):

That was coming!

OpenStudy (anonymous):

Are you trying to solve @mathmath333

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!