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OpenStudy (anonymous):
The area of sector JLK in Circle L is 3pi in^2. Find m arcJK.
OpenStudy (anonymous):
|dw:1412715804884:dw|
OpenStudy (anonymous):
First find the angle using the formula (theta/2pi)*pi*r^2
OpenStudy (anonymous):
Idk what theta is.
OpenStudy (anonymous):
theta is the angle you have to find
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OpenStudy (anonymous):
Since arc length is '(theta/2pi)*pi*r' :)
OpenStudy (anonymous):
Did you get it?
OpenStudy (anonymous):
I got 18
OpenStudy (anonymous):
@KissMyAxe
OpenStudy (anonymous):
18 what?
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OpenStudy (anonymous):
The angle.
OpenStudy (anonymous):
exactly 18
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
I think it is 0.52 radians
OpenStudy (anonymous):
I'm confused. Can you show me how to work it out? I understand better that way.
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
Do you know the final answer?
OpenStudy (anonymous):
No
OpenStudy (anonymous):
So to find the angle it would be:
(theta/2pi)*pi*r^2= 3pi in^2
on the LHS pi's cancel and we are left with:
(theta/2)*r^2= 3pi in^2
let me know if you have any problem up till here
OpenStudy (anonymous):
Where did you get 3pi in^2?
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OpenStudy (anonymous):
Well that's the are of sector, right?
OpenStudy (anonymous):
*area
OpenStudy (anonymous):
My book didn't have that in it. I couldn't find the word theta either. It must be a further lesson.
OpenStudy (anonymous):
I understand what you've done so far in the problem though.
OpenStudy (anonymous):
What are you going to rant about
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
Its nothing!
OpenStudy (anonymous):
Well here in A-levels we call the the angle theta. What do you guys call it?
OpenStudy (anonymous):
.....All I was saying was the reason I didn't know what you were talking about was because my book didn't teach me it.
OpenStudy (anonymous):
I don't know why you spazzed..
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OpenStudy (anonymous):
U were taking along time to answer :P
OpenStudy (anonymous):
Anyways we have to find the angle or theta
OpenStudy (anonymous):
Okay... I understand what you did so far in the problem.
OpenStudy (anonymous):
So angle= (2*3pi)/6^2
OpenStudy (anonymous):
Did you get this?
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OpenStudy (anonymous):
Yes, .52
OpenStudy (anonymous):
Okay than we use the formula 'Arc length= r*angle' Since the angle is in radians this formula is a simplified one
OpenStudy (anonymous):
3.12?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Okay, thanks.
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