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Mathematics 11 Online
OpenStudy (anonymous):

Simplify the expression: e^ln(5x+2)

OpenStudy (anonymous):

\[e ^{\ln (5x+2)}\]

OpenStudy (anonymous):

What is \[10^{\log_{10}100}\]?

OpenStudy (anonymous):

e and ln cancel out frend so 5x+2 is result

OpenStudy (anonymous):

@pkjag that is 100.

OpenStudy (anonymous):

@chungstonhill Thank you, I understand now.

OpenStudy (anonymous):

yes, its also the same for any \[e^{\ln(f(x))}\]

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