a spider has 8 legs, an ant has 6 legs, there are a group of spiders and a group of ants. the groups have a equal number of legs . what is the least number of spiders and ants in each group?
your basically looking for the least common denominator which is 24
To solve this, you must understand Least Common Multiple (LCM). To find the LCM, you have to find the lowest number where it can still divide evenly into both numbers. In the question, the two numbers are 6 and 8. The easiest way to find a multiple is to multiply both numbers by each other (in this case, 48). But, if the two numbers have a common factor, you can find one lower. To do this, you find the Greatest Common Factor (GCF). Then, you divide the first number (48) by the GCF (2), to get the LCM (24).
So, there are 24 spiders and 24 ants.
oops...I put least common denominator...lol
Do you understand?
the asker is not here
Oh, derp. Didn't realize.
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