Question

write a quadratic equation having the given numbers as solutions. -10/3,2

Answer 1

given numbers as solutions to what?

Answer 2

to the qe, I think

Answer 3

the term solution is ambiguous

are those roots? or something else

Answer 4

of course they are roots

Answer 5

f(x) = -10/3 and f(x) = 2 are also defined by the term 'solution'

Answer 6

i got 3x^2+3x-20=0 but im not sure if its right

Answer 7

well, to dbl chk, insert the solutions to see of its true

Answer 8

otherwise: a product of the roots would turn out:

(-10/3 - x) (2 - x)

(-10 - 3x) (2 - x)

3x^2 +20 -6x +10x

Answer 9

id try 4x instead of 3x

Answer 10

-20 ... my fingers hate me

Answer 11

its 3x^2+4x-20=0 i had to redo it thanks for the help though

Answer 12

youre welcome