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OpenStudy (anonymous):

Help with Calculus? This is the table. http://i198.photobucket.com/albums/aa84/ray51no/Cal_zpscd0b3373.png And the question is: Let Z(x) = g(x^2 + f(x)). Compute Z'(1). Any explanation on how to do this is appreciated!

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OpenStudy (anonymous):

f(g(x))'=g'(x)*f'(g(x)) soo analogically Z'(x)=(x^2+f(x))'*g'(x^2+f(x)) Z'(x)=(2x+f'(x))*g'(x^2+f(x)) z'(1)=(2+6)*g'(1+5) z'(1)=8*4=32

OpenStudy (anonymous):

There's an answer key that states the answer is supposed to be eight, which means all I have to do is know how to figure this out...

OpenStudy (anonymous):

I must have done something wrong. Let me do that again. (2x+f'(x)*g'(x^2+f(x)) x=1 (2+f'(1))*g'(1+f(1))= 8*g'(1+4)=8*1 okaay here it is ^^

OpenStudy (anonymous):

Thank you so much!

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