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OpenStudy (anonymous):
For a natural umber a, let aZ be the set of all integer multiples of a. Prove that for all a, b in the set of natural numbers, a=b iff AZ=bZ
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OpenStudy (math&ing001):
Let there be a and b in the set of natural numbers such as aZ=bZ. We have that a is in aZ and therefore in bZ so b|a. We have that b is in bZ and therefore in aZ so a|b. Since a,b>0 a=b.
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