Question

**MEDAL**
I'm creating flashcards to help me study for the ASVAB. Help me with some formulas?

A cardboard box has a length of 3 feet, height of 2½ feet, and depth of 2 feet. If the length and depth are doubled, by what percent does the volume of the box change?

A. 200%
B. 300% <--
C. 400%
D. 600%

Formula?

Answer 1

Volume change= volume of the changed - volume of the original

to get that into percent you multiply the resultant by (100/15)

Answer 2

vi=15
vf= 60
change in v is 45 and then multiply it by 100/15

Answer 3

Thanks again :)

Answer 4

Real quick @M0j0jojo
where did 60 and 15 come from? (I understand that 45 came from 60 - 15).

Answer 5

The formula for volume of a the box is LWH
so the original volume before the doubling is (3)(2.5)(2)=15
then the doubling happens and the dept and height are doubled so it becomes
L2W2H= (3)(2x2.5)(2x2)=60

percent of increase = (V2 - V1)/V1 = (60 - 15)/15 = 45/15 = 3

Answer 6

Ahh, that makes alot more sense! Fan for you, @M0j0jojo
Thanks again :)

Answer 7

No problem glad i could help :)