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Use the intermediate value theorem to show that the function has a real zero between the numbers -8 and 2 with the given function. 4x^2-2x-10
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i think what they want you do to is replace x by -8 and replace x by 2 one result will be positive, the other negative since the function is continuous it takes on all values between the two, and zero is between the positive and negative number
it is kind of a dumb question since \[f(x)=4x^2-2x+10\] is a quadratic, and so you can find the zeros exactly using the quadratic formula
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