Question

@triciaal

Answer 1

x^3 polynomial 3 roots

Answer 2

There's two answers with 3 roots.

Answer 3

Tri?

Answer 4

-1 is not a factor
1 is a factor
I substituted the values
I am not sure the systematic way to prove D

Answer 5

So D's the correct answer because -1 isnt a factor?

Answer 6

I think i have it switched
when x = 1 remainder = 0 so x-1 is a factor

Answer 7

So the correct answer would be C in that case?

Answer 8

yes

Answer 9

when we use the conjugate and "a" is positive it becomes a^2 + 1

Answer 10

It was incorrect :S I got like a 40 on this whole thing, algebra 2 sucks. lol.

Answer 11

sorry i am getting mixed up

Answer 12

complex numbers can be tricky

Answer 13

Its okay, I can retake. But I got these wrong:

Answer 14

product is -12 and sum +1 you know the numbers are 3, 4
you know one number is -ve because the product is -ve
how do you combine 3, 4 with + and - to get positive 1 ?

Answer 15

(x+ 4)(x -3)
roots -4 and 3 so A