Question

Simplify
2x^2-5x+3 x^2-4
--------- divided by ------------
4x^2-9 4x^2+14x+12

Answer 1

u mean 1st divided by 2nd

Answer 2

yes

Answer 3

it is very lenthy question.

Answer 4

@Kainui

Answer 5

u know factorization??

Answer 6

2x^2-5x+3=2x^2-3x-2x+3
=x(2x-3)-1(2x-3)=(2x-3)(x-1)

Answer 7

no

Answer 8

4x^2-9=(2x)^2-3^2=(2x-3)(2x+3)

Answer 9

\[\frac{ (2x-3)(x-1) }{ (2x-3)(2x+3)}\]

Answer 10

\[\frac{ x-1 }{ 2x+3 }\]

Answer 11

this is the simplified form?

Answer 12

no this is first part ....the part before divide

Answer 13

now term after divide

Answer 14

x^2-4=x^2-2^2=(x-2)(x+2)

Answer 15

4x^2+14x+12=4x^2+8x+6x+14

Answer 16

4x^2+8x+6x+12
=4x(x+2)+6(x+2)=(x+2)(4x+6)=(x+2)*2*(2x+3)

Answer 17

(x-2)(x+2)/(2*(x+2)(2x+3)=(x-2)/(2*(2x+3)

Answer 18

\[\frac{ x-1 }{ 2x+3 }\div \frac{ x-2 }{2( 2x+3 )}\]

Answer 19

\[\frac{ x-1 }{ 2x+3 }*\frac{ 2(2x+3 )}{ x-2}\]

Answer 20

\[\frac{ 2*(x-1) }{ x-2 }\]

Answer 21

simplified

Answer 22

woah that was alot of steps but i understand now thank you so much for helping me :)

Answer 23

welcome :)