Question

Happy Birthday! Or maybe Happy Un–Birthday? Either way, here is a fun birthday trick.

Take the month you were born in. Multiply it by 4, add 13, multiply by 25, subtract 200, add the day you were born, multiply by 2, subtract 40, multiply by 50, add the last two digits of your birth year, subtract 10500…. viola! Your birth date! Impress your friends!

Now, use your birthday for some more math fun.

You can locate graph paper here.

Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day.

Answer 1

Write your equation below.

Using complete sentences, explain how to convert your birthday function into standard form.

Graph your function. Include your graph below.

Using complete sentences, explain how to find the average rate of change for f(x) from x = 4 to x = 7.

My birthday is July, 18, 1998.

Answer 2

@pkjag
@One098
@monsterfox1997

Answer 3

@Niko_De_Angelo

Answer 4

ive worked on this all week n its over due bc i cnt do it ...n i cant afford an f in algebra 2 :"(

Answer 5

@ganeshie8 Do you know this?

Answer 6

Or know how to solve it?

Answer 7

f(x) = 1(x - 7)^2 + 18 to make it easy (the 1 is a, 7 is h and 18 is k) and then i would FOIL it out and get (x - 7)(x - 7) + 18 = x^2 - 14x + 49 + 18 = x^2 - 14x + 67 RIGHT?

Answer 8

yes

Answer 9

and to find average rate of change from 4 to 7, plug in 7 for x then plug in 4 for x. Subtract the answers and put this over (7 - 4) = 3

Answer 10

yes

Answer 11

but tht is the part where i am confused like i cant do the graph and tht

Answer 12

@just_one_last_goodbye
@PaulaLovesSchool13

Answer 13

Ur...what is the birthday part for?

Answer 14

omg xD thought this was a birthday party in MAth section

Answer 15

xD ^

Answer 16

i have no idea lol thts what i said .........and lol @just_one_last_goodbye

Answer 17

no but i seriously need help i did one part but the whol put 7 and x n all tht im lost

Answer 18

im sorry @morganchavez im not good at math i know a few people that are tho ^_^ but im great at History and stuff so if u need help on that just tag me

Answer 19

Same here, I can only do 6th grade or below math

Answer 20

ok can u tag those pple tht r please ive been on this for 3 days and it over due and dont i get it please

Answer 21

ok thank you @PaulaLovesSchool13

Answer 22

Morgan, what REALLY was the birthday stuff for?

Answer 23

thats what the teacher gave it to us like that n we had to use the numbers from our bday meaning the month and day to put it in the equation ....ull learn this in 11 grade lol it is very difficult

Answer 24

o_O teachers are becoming weirder and weirder

Answer 25

yasss and pain in tha butts

Answer 26

And also, I am in 8th grade o_O

Answer 27

lol yup ur almost there

Answer 28

@undeadknight26 @YanaSidlinskiy @texaschic101

Answer 29

thank u @just_one_last_goodbye ur awsome <3

Answer 30

lol u are <3 ^_^

Answer 31

I'm NOT smart.

Answer 32

-.= yesh u is

Answer 33

you are a mathlete dude

Answer 34

^ lol xD

Answer 35

act like one o_O

Answer 36

fghabgruigba;kergbjaregba;gbiuargba;rgbrbg <------ That's what I got!!! I'm a Mathlete!!:)

Answer 37

O_o

Answer 38

Yana, come on

Answer 39

unless u have to answer my math questions =_=

Answer 40

This is Random!! It's not really my Birthdate. My Birthdate is March.
My birthday, just for practice: October 4, 1980
10 * 4 = 40 + 13 = 53 * 25 = 1325 – 200 = 1125 + 4 = 1129 * 2 = 2258 – 40 = 2218 * 50 = 110900 + 80 = 110980 – 10500 = 100480.
The trick is that 100480 can be sub-divided down to 10 04 80, which is my birthday in the form (mm/dd/yy).

Answer 41

o_O

Answer 42

OMg, lol!! Idk wut that is. It's only numbers....Lemme see if I can get a screenshot, from my word document. I had the same question before, Morgan. Found it in my Microsoft word!!:) Hang tight,xD!!

Answer 43

average rate of change may mean the differential of your function \[\frac{df}{dx}\]

Answer 44

thank you sorry it took me forever to respond ....personL ISSUE feeling ill

Answer 45

actually i'm the one who took forever, do you know how to differentiate a function?

Answer 46

no

Answer 47

is this a homework/coursework question?

Answer 48

yes

Answer 49

@TheSmartOne
@Teddyiswatshecallsme
@almightyemery***
@boxhead06
@ameenbriscoe13
@ObeyBaby_nemo
@J-bird
@kavonta

Answer 50

hey

Answer 51

do you how to graph a quadratic function using the values

Answer 52

im sure i culd figure it out probably

Answer 53

n hi

Answer 54

hey morgan

Answer 55

its your bday

Answer 56

no its a math assinment

Answer 57

ooohhh

Answer 58

lol

Answer 59

f(x) = 2(x - 6)^2 + 1 The vertex of this graph is at (6,1) If born 2 months earlier and 5 days later, (h,k) will be (4, 6) and f(x) will be: f(x) = 2(x - 4)^2 + 6 The vertex of this graph will be at (4,6) This will shift the graph 2 units to the left and 5 units up.

Answer 60

just put in values of \[x=0\] to \[x\ge7\] in your function \[f(x)\]then the values you get for each \[x\] are a different \[y\]so you have to draw a table, then for all values \[(x,y)\]you get plot them on the graph

Answer 61

thank you @pkjag and @ameenbriscoe13

Answer 62

wc

Answer 63

anytime

Answer 64

@woooooooooowwwww

Answer 65

medal please