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prove cos^4(A) - sin^4(A) =cos2A @ganeshie8 for this, it's powers, so i can't use the previous method you hinted, right? and how can cos^4(A) - sin^4(A) = cos^2(A) - sin^2(A)
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or if anyone else can provide an adequate explanation, that'd be cool :3
hint1 : a^2 - b^2 = (a+b)(a-b)
hint2 : sin^2A + cos^2A = 1
\[\large \cos^4A - \sin^2A = (\cos^2A)^2 - (\sin^2A)^2\]
\[\large = (\cos^2A+\sin^2A)(\cos^2A-\sin^2A)\]
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\[\large = (1)(\cos^2A-\sin^2A)\]
whoa okay I got it through the hint thank you :3
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