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do you know what \(\bf (f\circ g)(x)\ or \ (g \circ f)(x)\) mean?
Of course.
What I don't understand is, what do I do with that -5 and 0.
hmmm on which one?
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Like number 3 and 4
By the way, on number 2 is it like the same as any (Fog)? Same process, and such..?
that's the argument value for "x" in the combined equation
How do I apply it?
\(\bf f(x)=2x+1\qquad {\color{brown}{ g(x)}}=x^2\qquad (f\circ g)(x)=2({\color{brown}{ x^2}})+1 \\ \quad \\ (f\circ g)({\color{blue}{ -5}})=2({\color{brown}{ ({\color{blue}{ -5}})^2}})+1\)
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God damn it! That's how you finish it off. Okay. Thanks. I'll solve it from here.
yw
@jdoe0001
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