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Mathematics 21 Online
OpenStudy (anonymous):

Damn. Not getting the right answers /(-_-)\

OpenStudy (anonymous):

OpenStudy (jdoe0001):

do you know what \(\bf (f\circ g)(x)\ or \ (g \circ f)(x)\) mean?

OpenStudy (anonymous):

Of course.

OpenStudy (anonymous):

What I don't understand is, what do I do with that -5 and 0.

OpenStudy (jdoe0001):

hmmm on which one?

OpenStudy (anonymous):

Like number 3 and 4

OpenStudy (anonymous):

By the way, on number 2 is it like the same as any (Fog)? Same process, and such..?

OpenStudy (jdoe0001):

that's the argument value for "x" in the combined equation

OpenStudy (anonymous):

How do I apply it?

OpenStudy (jdoe0001):

\(\bf f(x)=2x+1\qquad {\color{brown}{ g(x)}}=x^2\qquad (f\circ g)(x)=2({\color{brown}{ x^2}})+1 \\ \quad \\ (f\circ g)({\color{blue}{ -5}})=2({\color{brown}{ ({\color{blue}{ -5}})^2}})+1\)

OpenStudy (anonymous):

God damn it! That's how you finish it off. Okay. Thanks. I'll solve it from here.

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

@jdoe0001

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