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OpenStudy (mtalhahassan2):
0,-3
OpenStudy (mtalhahassan2):
how can we graph this?
OpenStudy (aum):
Are you familiar with the graph of y = x^2 ?
OpenStudy (mtalhahassan2):
Is we have to used the table of value?
OpenStudy (mtalhahassan2):
yeah I am
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OpenStudy (mtalhahassan2):
tell me the easier way
OpenStudy (aum):
If you are familiar with y = x^2, then the graph of y = x^2 - 3 is just the graph of y = x^2 shifted DOWN by 3 units.
OpenStudy (aum):
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OpenStudy (aum):
If you are asked to do it by table then put x = -3, -2, -1, 0, 1, 2, 3 and calculate the y values. Plot the point and draw a graph:
x f(x)=x^2 - 3
-3 (-3)^2-3 = 6
-2
-1
0
1
2
3
OpenStudy (mtalhahassan2):
like the value of original be 0,0, 1,1 2,2
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OpenStudy (mtalhahassan2):
which way is more easier
OpenStudy (mtalhahassan2):
the table of value or just drawing the original graph then changing the points
OpenStudy (aum):
No. That will be for y = x^2
Here it is y = x^2 - 3
So you have to plug in each x value and calculate the y-value.
Depends on what they are expecting. If they just want a general sketch the first method is easier. If they want an accurate plot the second method of table has to be used.