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Mathematics 13 Online
OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

2 ducks and 1 snail

OpenStudy (anonymous):

Hey, I still need help with that bs.

OpenStudy (jdoe0001):

well... you can always post =)

OpenStudy (anonymous):

OpenStudy (anonymous):

When it says, gof, how do I set that up?

OpenStudy (anonymous):

Just the same thing as fog?

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

So, it'll be this, 2x(4x+7)-3?

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

Almost done. I got the answer, not sure if I did this right. My answer is -3

OpenStudy (jdoe0001):

hmmm actually hmmm you kept the x there... should be 2(4x+7)-3

OpenStudy (jdoe0001):

\(\bf {\color{brown}{ f(x)}}=4x+7\qquad g(x)=2x-3\qquad (g\circ f)(x)=2({\color{brown}{ 4x+7}})-3 \\ \quad \\ (g\circ f)({\color{blue}{ 0}})=2({\color{brown}{ 4({\color{blue}{ 0}})+7}})-3\) check closely

OpenStudy (jdoe0001):

the "x" gets replaced by the argument, thus

OpenStudy (anonymous):

So just take that x out of the 2?

OpenStudy (jdoe0001):

yes because the argument "f(x)" will take it over

OpenStudy (anonymous):

Oh man, they're about to fight.

OpenStudy (anonymous):

It's 11

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

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