The graph of f passes through (-9, 10) and is perpendicular to the line whose equation is x=9
put in slope intercept form

Question

The graph of f passes through (-9, 10) and is perpendicular to the line whose equation is x=9
put in slope intercept form

anonymous · Answer

webwork doesn't give me an example of how to solve one like this

anonymous · Answer

We we got a very simple problem here, what is the slop of x = 9 when looking at its graph or just remembering?

anonymous · Answer

is it just 9?

anonymous · Answer

oh wait

anonymous · Answer

0?

anonymous · Answer

Nope that would be is y = 9, x = 9 is a vertical line so it has no slop so the line perpendicular to it would have a zero slope

anonymous · Answer

so knowing that y = 10, x=-9 and m=0 you plug those into the standard slope-intercept form of 

y=mx+b and solve for be and you will end up with a equation like y=b

anonymous · Answer

thank you :)

anonymous · Answer

No problem, always here to help people!