Your sock drawer holds 8 black, 4 tan, and 15 brown socks. Without looking, you grab one sock. find the probability the sock is not brown

Question

anonymous · Answer

@bibby

anonymous · Answer

I would guess 12/27 but i'm not sure

bibby · Answer

$\huge\frac{p(brown)}{p(total)}$

bibby · Answer

wait why are there 15 brown socks

bibby · Answer

who has odd numbers of socks

anonymous · Answer

lol

bibby · Answer

anyhow assuming you meant 15/27, you're right. it can be simplified to 5/9

anonymous · Answer

I might since I mix-match anyway

shinalcantara · Answer

Since this involves combination then you'll have it as:
$$\frac{ _{12} C_1  }{ _{27} C_1 }$$

anonymous · Answer

well there's 27 all together and 15/27 so then the probability of not getting brown is 12/27 or 4/9

bibby · Answer

what combinations? you're picking one

anonymous · Answer

Thnank you bibby

bibby · Answer

wait I misread the question. raven got it right

anonymous · Answer

what one of you got 5/9 one of you got 4/9

bibby · Answer

the probability of brown is 15/27

not brown is 12/27, sorry

anonymous · Answer

ok no prob

anonymous · Answer

thanks raven