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4(r - 1) + 6 < 2r + 12
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Are you supposed to solve for r?
yes
If so. Start by distributing the left value. 4(r-1)
ok
r < 14 r < 12 r < 6 r < 5
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which of them are right
4(r - 1) + 6 < 2r + 12 4r-4+6<2r+12 4r+2<2r+12 4r<2r+10 2r<10 r<5 It's r<5
what bout this one Solve: -3p > -9 p < 3 p > 3 p < -3 p > -3
divide by -3. -9/-3= 3 When you divide by a negative the sign switches. p<3
what bout this one Solve for t if 5|t| = -10 t = 2 t = -2 t = -2, 2 No solution
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divide by 5. -10/5 is -2. you have absolute value of t. So whether is -2 or 2 is going to equal 2. So t=-2,2
ok thanks
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