Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

4(r - 1) + 6 < 2r + 12

OpenStudy (anonymous):

Are you supposed to solve for r?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

If so. Start by distributing the left value. 4(r-1)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

r < 14 r < 12 r < 6 r < 5

OpenStudy (anonymous):

which of them are right

OpenStudy (anonymous):

4(r - 1) + 6 < 2r + 12 4r-4+6<2r+12 4r+2<2r+12 4r<2r+10 2r<10 r<5 It's r<5

OpenStudy (anonymous):

what bout this one Solve: -3p > -9 p < 3 p > 3 p < -3 p > -3

OpenStudy (anonymous):

divide by -3. -9/-3= 3 When you divide by a negative the sign switches. p<3

OpenStudy (anonymous):

what bout this one Solve for t if 5|t| = -10 t = 2 t = -2 t = -2, 2 No solution

OpenStudy (anonymous):

divide by 5. -10/5 is -2. you have absolute value of t. So whether is -2 or 2 is going to equal 2. So t=-2,2

OpenStudy (anonymous):

ok thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!