find the area of a triangle who's base is x^2+2x+4 and who's height is 2x^2+2x+6 (will fan and medal)
area = 1/2 * base * height
did that help?
I already knew that but thank you anyway \(\color{lime}{\Huge\ddot\smile}\)
@haleyelizabeth2017 @Bookworm14
so you know the formula to find the area of the triangle substitute the expressions and simplify. use what you know to find the unknown
find the Area 1/2 * base * height 1/2 * (x^2+2x+4) * (2x^2+2x+6)
I tried but it didn't work :(
I got 2x^3+6x^2+22x+12
(x +2)(x^2 + x + 3)
x^3 + x^2 + 3 x + 2 x^2 + 2 x + 6 Area = x^3 + 3 x^2 + 5 x + 6
check your term in x and did you divide by 2 ?
yes
I tried two times but I still couldn't get it :(
is my answer correct? do you want to post what you did? the difference between mine and yours is the term in x and the factor
sorry, your answer wasn't one of my choices
i have an error (x +2)(x^2 + x + 3) should be (x +2)^2
Area =(x^3 + 3 x^2 + 5 x + 6 )(x + 2) = x^4 + 5 x ^3 + 11 x ^2 + 16 x + 12
sorry, my choices are A. 3x^4+9x^2+10x+12 B. x^4 +3x^3+9x^2+10x+12 C. 3x^4+3x^3+9x^2+10x+12 D. x^4+9x^2+10x+12
x^4 + 3 x^3 + 9 x^2 + 10 x + 12
the correct answer is B
re do the process is correct 1/2 * 2(x^2 + x + 3)(x^2 + 2 x + 4)
thank you :)
sorry about my previous calculation errors you are welcome
Join our real-time social learning platform and learn together with your friends!