Question

(2x+5)/X^2-3x-10 +(x+1)/x+2

Answer 1

Use parenthesis to group items so we know which part is in the denominator and which is not. Is the entire (x^2 - 3x - 10) in the denominator? If so, factor it first.

Answer 2

Yeah that pretty much sums it up

Answer 3

no at aum i put den to seperate cuz on the original problem its not there

Answer 4

@aum

Answer 5

@kohai i kinda need the work

Answer 6

The original problem may not have parenthesis because they can put the numerator on top, draw a line and then put the denominator at the bottom and so it is clear which is on top and which is on the bottom. But when you write horizontally you have to put parenthesis to group things together so it is clear which is on top and which is at the bottom. The way you have written it without parenthesis will most likely be wrongly interpreted as follows:\[
(2x+5)/x^2-3x-10 +(x+1)/x+2 \\
\frac{2x+5)}{x^2} - 3x - 10 + \frac{(x+2)}{x} + 2
\]

Answer 7

@aum its exactly like the first one

Answer 8

can you tell me how to properly solve this? @camillamartin95

Answer 9

@aum

Answer 10

@kohai

Answer 11

@gorv