Question

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the distance in 4.5 h. Car B traveled 5 mph slower than Car A.

How fast did Car B travel?

Answer 1

guess we need the old "distance equals rate times time"

Answer 2

for car A, if you call the rate \(R\) and the distance \(D\) then \(4R=D\)
since car B goes 5 mph slower, its rate is \(R-5\) and
\(4.5(R-5)=D\)

Answer 3

since evidently the distance is the same, you can set them equal and solve
\[4R=4.5(R-5)\]for \(R\)