I need help with 4 questions... ;n; Monomials and polynomials... (attached below)
I think 7 is false... I'm not sure about the other three though. . .
8..... I think A... Maybe?
9 and 10, the infinity throws me of... I have no idea.
7,8 are correct! for 9 and 10, just plug in the value of x as \(\infty \quad and \quad -\infty \)
take the sign of the highest exponent of x
For number 9 it would be 4 and 10, 3... Where would I plug them in at? ;o
for example , \(with \: x \to \infty , \quad x^3-x^2 \to +\infty \) \(with \: x \to -\infty , \quad x^3-x^2 \to -\infty \)
for 9th, since it is -x^4 plugging in x= infinity there, gives you -infinity
... Because the x is negative, It made the infinity negative?
x is positive , so x^4 is positive so - x^4 will be negative :)
in 10th, x is negative so 2x^3 will also be negative!
just think of infinity as a very large number!
So..... Then 9 would be true and 10 would be false?! :O What yhu just did. Was at leat a bagillion times easier then how my teacher and tutor were trying to teach me...
Least*
9 will be false right ? as x is positive, f(x) will be negative
because you have -x^4 there, which will be negative
Ohhhhhh... Oh my gosh... So then 10... Would aslo be false? ... No it'd be true! Because the x is negative... and f(x)... It's positive... Right?
x is negative 2x^3 will be negative f(x) will be negative false
-2x^3 will be positive, but we have +2x^3 in the question
Right. So if in the question, f(x) is +2x^3, why would the f(x) --> positive infinity be wrong?
because since x is negative, x^3 is negative, +2x^3 is negative and f(x) is negative
as i said, think of infinity as a very large number say when x is negative infinity take x= -9999999999999999999
when x is +infinity take x = 99999999999999999
>O< Oh! I missed the cubic root... That's where... Oh... Alright. >u<
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