hello
could you guys help me on this geometry question
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OpenStudy (anonymous):
OpenStudy (jackky):
um sure if you would put the ? there
hartnn (hartnn):
concentrate on triangle XAB
find XA
know how to ?
OpenStudy (jackky):
me
hartnn (hartnn):
XA and AB
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OpenStudy (anonymous):
i don't know because i only have angles but not the lengths
OpenStudy (gorv):
u know about right angle triangle ??
hartnn (hartnn):
take XB as 'a'
hartnn (hartnn):
'a' will eventually get cancelled out while taking tan ratio
OpenStudy (anonymous):
i understand
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OpenStudy (anonymous):
thanks i will try
OpenStudy (anonymous):
no i don't understand i m sorry i could nt did that
OpenStudy (amistre64):
i was going to suggest using 1 as the side of a square for simplicity
OpenStudy (anonymous):
ok...but it is right to take 1 as a side of the square?
hartnn (hartnn):
ok, if XB = a
what is XA ?
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OpenStudy (amistre64):
any measure will work since this is good for any size square
OpenStudy (amistre64):
pick your favorite size :)
OpenStudy (anonymous):
XA= acos60
hartnn (hartnn):
yes
which is ?
also find AB
OpenStudy (anonymous):
ok thanks @amistre64 i think i can do it
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OpenStudy (amistre64):
i think you can do it to ;)
hartnn (hartnn):
if not, we are here :)
OpenStudy (anonymous):
but AB= 1 ?
hartnn (hartnn):
fix any 1 length
you can take AB =1
OR
XA = something, anything , 1, ...
OpenStudy (amistre64):
the picture itself is misleading, they angle they marked 'looks like' a 60 but we have to go with the information given.|dw:1413033102679:dw|
this is more accurate