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if f(x)=ax+b where a and b are constants, find a and b for f(1)=-4 and f(3)=2
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So when x=1 y=-4 and when x=3 y=2
f(1)=a(1)+b -4=a+b and f(3)=a(3)+b 2=3a+b
So you need to solve the two equations by substitution or elimination -4=a+b 2=3a+b
you can just subtract both of them and eliminate b and you will get -6=-2a
divide by -2 and a=3
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now plug in a=3 and -4=3+b b=-7
So your solutions are a=3 and b=-7 @philosophia
thank youuu :) @TheSmartOne
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