y = -x2 + 8x - 12 a.) Identify the location of the vertex b.) Identify the location of the x-intercept(s), if any c.) Identify the location of the y-intercept d.) Write the equation for the axis of symmetry (I'm having trouble converting this from standard to the other forms.)
Do you know how to find the vertex? Do you know what an x and y intercept is?
I thought I had the formula for vertex, but I guess I had the formula for point slope and was getting them mixed up... >.< I don't know the formula for vertex
Vertex=\[(\frac{ -b }{ 2a},f(\frac{ -b }{ 2a}))\] in the form of (x,y)
I just plug in a and b and find it and that's my vertex?
yes and then whatever you get from -b/2a you plug that back in to find the y value.
Or you can graph it and then see where everything is...
You will notice that the vertex is (4,4)
Would it be 4 or -4?
Oh :D haha...
Look at the graph.. You can see the vertex and even the intercepts...
Yes. c: How would I calculate the intercepts?
y intercept is when x=0 and you solve for y x intercepts is when y=0 and you solve for x
but if you look at the graph you see the x-intercepts is (2,0) and (6,0) and the y-intercepts is (0,-12)
So, I would set x=0 ... To find the y intercept? Or the x?
Axis of symmetry is \[x=\frac{-b}{ 2a }\]
Yes you would make x=0 to find the y-intercept and solve for y and your point would be (0,y)
This graph includes the axis of symmetry.
So do you have any more questions?
@Ria23
Uhm... I think, I have it... If I get stuck anywhere I'll tag yhu c: Thank yhu for helping me! I appreciate it!
no problem...\[\huge\color{red}{\ddot\smile}\]
@ria23 If your question is solved.. you can close this question...
@TheSmartOne I'm having trouble identifying how I find the x-intercepts. If I set y=0, that'll give me 0=x^2+8x-12 How would I solve for the x's... I have my graph drawn, but I need to show my steps on how I got it
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