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Mathematics 7 Online
OpenStudy (anonymous):

http://openstudy.com/study#/updates/52bf0bb3e4b0fef2cb9e0e2d Plz go to this website on open study this is the question it's the gorden one i need help I'll follow give medal anything If that doesent work then search up Gordon is evaluating some stocks he wants to purchase and it will pop up

OpenStudy (anonymous):

@mathmath333

OpenStudy (mathmath333):

Gordon is evaluating some stocks he wants to purchase. You can see the function of the stock price below. The variable x represents days. Stock A B C Price A.) f(x) = 25(1.08)x B.) x f(x) 0 22.00 1 21.56 2 21.13 C.) The initial price of this stock is $30, but it has been increasing 4% each day. 1.) Create the price function for Stock D. It should have the second lowest starting price and the second highest rate of growth. Using complete sentences, justify that your function meets these requirements. 2.) Graph the price function for Stock D. Explain the key features of the graph with complete sentences. 3.) A recent drop in sales has affected Stock D with the function g(x) = –6. Explain to Gordon how Stock D’s new price function, f(x) + g(x), will be created. Graph f(x) + g(x). 4.) Gordon wants to fully understand what kind of changes could affect the money he is investing. Using complete sentences, explain the effect of the following transformations. Graph them and f(x) on the same coordinate plane. f(x + 2) f(–x) f(x) + 3

OpenStudy (mathmath333):

for \(\large\tt \color{red}{A}\) \[\large f(x)=25(1.08)^x\] \(\large\tt \color{black}{A~~initial ~~value =25}\) it is equal to \(\Large\tt \color{blacck}{increase}\) in for \(\Large\tt \color{blacck}{8\%}\) per day for \(\large\tt \color{red}{B}\) \(\large\tt \color{black}{B~~initial ~~value =22}\) \(\large\tt \color{black}{21.56=22(0.98) =22(1-0.02)}\) hence for B it will be \(\Large\tt \color{blacck}{decrease}\) in \(\Large\tt \color{blacck}{2\%}\) per day for \(\large\tt \color{red}{C}\) it is already given \(\large\tt \color{black}{C~~initial ~~value =30}\) it is equal to \(\Large\tt \color{blacck}{increase}\) in for \(\Large\tt \color{blacck}{4\%}\) per day for\(\large\tt \color{red}{D}\) second lowest starting price=\(\large\tt \color{black}{25}\) second highest rate of growth=\(\large\tt \color{black}{4\%}\) there for function for D will be \(\Large\tt \color{black}{f(x)=25(1.04)^x}\) x f(x) 0 24 1 26 2 27.04 the graph will look like this |dw:1413151885388:dw|

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