Question

Help with trig substitution.

Answer 1

\[\int\limits (\sqrt{x^2-4)/4 }\]

Answer 2

\[\int\sqrt{\frac{x^2-4}{4}}~dx~~?\]

Answer 3

yes

Answer 4

i got to \[\int\limits2\tan^2x\]

Answer 5

ughhh im so sorry.... its an x in the denominator not a 4...

Answer 6

So\[\int\sqrt{\frac{x^2-4}{x}}~dx\]
and \(x\) is definitely inside the square root too?

Answer 7

yes

Answer 8

Hmm... What do you know about elliptic integrals?

Answer 9

I think you meant
\[\int\frac{\sqrt{x^2-4}}{x}~dx\]
The one above doesn't have an elementary result.

Answer 10

IM SO SORRRRRRY AGAIN Lol yes i meant that =[

Answer 11

i promise thats all the errors lol