Question

HELPPP please, these 3 questions

Answer 1

We aren't allowed to help people on their tests or quizzes, @sheetalvee

Answer 2

sorry :( Good luck, maybe don't have youtube open

Answer 3

Its an online practice quiz to prepare us for our quiz tomorrow but its timedd

Answer 4

Oh, well, you should study a little harder and maybe ask your teachers for help if you don't understand something (:

Answer 5

Quotient rule for the first one, product rule for the second one, and third one is just a sum so differentiate it normally.

Answer 6

Btw it says "watch it" so why not take advantage of that, I'm sure those videos are helpful.

Answer 7

For the first one, ill show you what U got what I got so far, and they're not useful, they just repeat the question slower

Answer 8

(1-cotx)(4)-(4x)( for the derivative of 1-cotx, that's where I got kinda stuck

Answer 9

What's the derivative of 1?

Answer 10

Or really any cosntant

Answer 11

oh -cot

Answer 12

derivative of 1 is zero

Answer 13

Yeah it's 0..what's the derivative of cotx?

Answer 14

so then (1-cotx)(4)-(4x)(-cotx) / (1-cotx)^2 ?

Answer 15

\[\frac{ f'g-g'f }{ g^2 }\] this is the quotient rule

Answer 16

Yes but now you have to get the derivative of f and g

Answer 17

and it should be -(4x)(1-cotx)

Answer 18

f' and g' means derivative

Answer 19

Okay so ill show you what I have on the paper Im getting confused

Answer 20

Well, I dont know where its -(4x)(1-cotx) .... I got (1-cotx)(4)-(4x)(-cot1) / (1-cotx)^2

Answer 21

You're missing the crucial point here

Answer 22

this is the quotient rule do you agree?