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Mathematics 9 Online
OpenStudy (anonymous):

evaluate cos^-1 (0)

OpenStudy (anonymous):

you know a number whose cosine is zero?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what is it?

OpenStudy (anonymous):

oh no sorry just evaluate that equation in terms of pi or sqrt, is what it is asking

OpenStudy (anonymous):

let me ask again do you know a number whose cosine is zero? i.e. what is \(\theta\) if \(\cos(\theta)=0\) ?

OpenStudy (anonymous):

1?

OpenStudy (anonymous):

hmm no

OpenStudy (anonymous):

it is true that \(\cos(0)=1\) but that is not the question what number would you put IN to get OUT zero

OpenStudy (anonymous):

90

OpenStudy (anonymous):

yes, except i think you are working with numbers (radians) not degrees, so it is \(\frac{\pi}{2}\)

OpenStudy (anonymous):

so since \[\cos(\frac{\pi}{2})=0\] you have \[\cos^{-1}(0)=\frac{\pi}{2}\]

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