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Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a brown marble, not replacing it, and picking another brown marble?
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brown: 1/19, brown: 0
You can't do that..because there is only 1 brown marble. So you can't pick 2 brown marbles. Therefore the probability is 0.
yea its just 0
Thats what I thought because there was only 1 brown marble. I din't know if my answer could just be "zero"
Oh, well is it multiple choice?
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There's NO chance of picking 2 brown marbles because you only have ONE brown marble. So it has to be 0.
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