Question

Solve by substitution.

4x − 12y = 5
x = 3y + 1











(1, 4)










(0, 1)










No solution










(negative-1, negative-2)

@iGreen

Answer 1

Question : 4x − 12y = 5
x = 3y + 1

Solving for y : 4(3y + 1) - 12y = 5

12y + 4 - 12y = 5

12y - 12y = 1

y = 1

Solving for x : 3(1) + 1

3 + 1

x = 4

ANSWER : (1,4)

Answer 2

Solve by substitution.

4x − y = 12
negative-2x + 2y = 6











(1, 4)










(5, 8)










(2, 2)










(negative-1, negative-3)






@Kaydex

Answer 3

no, its just -1,-3

Answer 4

:)

Answer 5

do you know how to do it?

Answer 6

@iGreen

Answer 7

@iGreen