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What's the partial derivative of (x+2)(x-3)y with respect to x?
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@ganeshie8
\[\begin{align*} \frac{\partial }{\partial x}\left[(x+2)(x-3)y\right]&=\frac{\partial }{\partial x}[x+2](x-3)y+(x+2)\frac{\partial }{\partial x}[x-3]y\\&~~~~~~~~+(x+2)(x-3)\frac{\partial }{\partial x}[y]\\\\ &=(x-3)y+(x+2)y+0\end{align*}\]
So the answer is (2x-1)y, right?
Yes
Thanks.
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