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x^2+(y+3)^2=10
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I can't see your question clearly.
and what do u need to do ? find center and radius of that circle ?
Yea @hartnn i cant figuer it out
for \((x-h)^2 + (y-k)^2 =r^2 \) the center is (h,k) and radius =r compare your equation with this general form
compare y+3 with y-k what do you get k as ?
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C=(o,-3) R=3.1 ?
Center is correct! :) radius you can keep it as \(\sqrt {10}\) or approximately 3.1 is also fine :)
Thank You so much =^_^=
welcome ^_^
since you seem to be new here, \(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
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