Question

Find the x-intercepts for the equation
y=-x^2+8x-12

Answer 1

x-intercepts is where y=0, so you have \[-x^2+8x-12=0\]

Multiply both sides by -1, then try to factor.

Answer 2

\[x ^{2}-8x+12=-1 \]
? ;o

Answer 3

So multiplying 0 by -1 will get you -1?

Answer 4

xD Oh... Oops. . .

Answer 5

Haha, so yeah; \(x^2-8x+12=0\)

Can you factor it?

Answer 6

(x-2)(x-6) ?

Answer 7

Yep, so you have \((x-2)(x-6)=0\)

So either \((x-2)\) or \((x-6)\)must be equal to 0.

So you have two cases:
\[x-2=0\\~\\x-6=0\]
Can you find the value of x?

Answer 8

Positive 2 and 6...

Answer 9

Yep, that's your answer:

(2,0) and (6,0)

Answer 10

Welcome.

Answer 11

^_^ Thank yhu!~