Question

Write the equation in standard form for the line that passes through the points ( - 5, 1 ) and ( 6, -2 ).

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -5}}\quad ,&{\color{blue}{ 1}})\quad &({\color{red}{ 6}}\quad ,&{\color{blue}{ -2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and move everything to the left}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 2

y=mx+b
do y2-y1/x2-xiget slope
and use a y value for b
mx is slope

Answer 3

Standard Form Is Ax+By=C

Answer 4

3x+11y=-4 is the answer

Answer 5

got it

Answer 6

thank you

Answer 7

np bye