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Solve for x: −3|2x + 6| = −12 A.) x = 1 and x = 5 B.) x = −1 and x = −5 C.) x = −9 and x = 3 D.) No solution
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First I would divide both sides by that number in front of the | |
You could also do |2x+6|=|2|*|x+3|=2|x+3| and also divide both sides by 2 but it isn't needed to do at this step
use the definition of absolute value to come up with two different equaitons |f(x)|=f(x) if f(x)>=0 |f(x)|=-f(x) if f(x)<0
we have two cases
Solve 2x+6=4 and solve also -(2x+6)=4
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so x=-1 and x=-5?
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