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Mathematics 16 Online
OpenStudy (ashy98):

Solve for x: −3|2x + 6| = −12 A.) x = 1 and x = 5 B.) x = −1 and x = −5 C.) x = −9 and x = 3 D.) No solution

OpenStudy (freckles):

First I would divide both sides by that number in front of the | |

OpenStudy (freckles):

You could also do |2x+6|=|2|*|x+3|=2|x+3| and also divide both sides by 2 but it isn't needed to do at this step

OpenStudy (freckles):

use the definition of absolute value to come up with two different equaitons |f(x)|=f(x) if f(x)>=0 |f(x)|=-f(x) if f(x)<0

OpenStudy (freckles):

we have two cases

OpenStudy (freckles):

Solve 2x+6=4 and solve also -(2x+6)=4

OpenStudy (ashy98):

so x=-1 and x=-5?

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