Identify the location of the x-intercept
y=3x^2+x-4
I'm so confused~ ; n;

Question

Identify the location of the x-intercept
y=3x^2+x-4
I'm so confused~ ; n;

adamaero · Answer

coordinates:
where does line intercept x?

ria23 · Answer

Uhm... Not sure... That what I need to figure out... :c

I set y=0, so I had 3x^2+x-4
But I'm not sure what my factors would be~ The 3 in front of the x'2 is confusing me...

anonymous · Answer

In this case, you would have to set "y" equal to 0 and solve from then on. So 0=3x^2+x-4. by factoring, you get 0=(x+1)(3x-4). By using the zero product property, set x+1 equals to zero and 3x-4 equal to zero. so you got your x values to be -1 and 4/3. put these in ordered pairs and (-1,0) along with (4/3,0) are your intercepts.

ria23 · Answer

;o Thank yhu for explaining that! c:

anonymous · Answer

no problem!