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f(x)=2(x-6)^2+4 how do u convert f(x) in to standard form
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\[\large \bf f(x)=2(x-6)^2+4\] just open the bracket,
\[\large \bf (a-b)^2=a^2+b^2-2ab\]
so we get, \[\large \bf f(x)=2(x^2+36-12x)+4\]
mayankdevnain could u please help me
understood? @ladystarkzombieslayer
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sure.. @zaqwsxedcrfv
come to my question pl
now,expand, \[\large \bf 2x^2+72-24x+4\] and then solve rest of the part
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