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OpenStudy (anonymous):
Anyone willing to help me study some math for my exam tomorrow? Please and Thank you:)
(I will ask questions below)
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OpenStudy (anonymous):
I'll help if I can.
OpenStudy (anonymous):
I need to know how to find the Domain for this equation.
\[f(x)=\sqrt{13-x}\]
OpenStudy (anonymous):
sure but what kind of math
OpenStudy (anonymous):
College Algebra:)
OpenStudy (anonymous):
sure then you need help on finding the domain? How would you start?
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OpenStudy (anonymous):
By taking the square root off?
OpenStudy (anonymous):
mmm yes and no, so finding the domain just really means finding the range of x's where y is a real number right?
OpenStudy (anonymous):
Correct
OpenStudy (anonymous):
How could I begin by doing that?
OpenStudy (anonymous):
so what can't be under the sqrt?
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OpenStudy (anonymous):
Negatives
OpenStudy (anonymous):
correct so in other words: \[13 - x > 0\] right?
OpenStudy (anonymous):
is it not \[13-x \ge0\]
OpenStudy (anonymous):
oh sorry yes you are correct!
OpenStudy (anonymous):
Okay, \[13-x \ge 0\]
subtract -13both sides, I get -13 and then divide it by -1 which would be positive 13
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OpenStudy (anonymous):
Will my sign change to less than? like this >
OpenStudy (anonymous):
|dw:1413267098765:dw|
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