Anyone willing to help me study some math for my exam tomorrow? Please and Thank you:) (I will ask questions below)
I'll help if I can.
I need to know how to find the Domain for this equation. \[f(x)=\sqrt{13-x}\]
sure but what kind of math
College Algebra:)
sure then you need help on finding the domain? How would you start?
By taking the square root off?
mmm yes and no, so finding the domain just really means finding the range of x's where y is a real number right?
Correct
How could I begin by doing that?
so what can't be under the sqrt?
Negatives
correct so in other words: \[13 - x > 0\] right?
is it not \[13-x \ge0\]
oh sorry yes you are correct!
Okay, \[13-x \ge 0\] subtract -13both sides, I get -13 and then divide it by -1 which would be positive 13
Will my sign change to less than? like this >
|dw:1413267098765:dw|
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