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Mathematics 9 Online
OpenStudy (anonymous):

Polygon help please.?

OpenStudy (aum):

If you post the question people may be able to help.

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm not asking for the answer straight out. I would like your help so I can understand for future tests. @aum

OpenStudy (aum):

The four internal angles of a quadrilateral adds to 360 degrees.

OpenStudy (anonymous):

4 sides but 1 is slightly slanted...

OpenStudy (anonymous):

So, how do I find "x"?

OpenStudy (anonymous):

u have a protractor?

OpenStudy (aum):

Add the 4 angles given and equate it to 360. 110 + (x + 10) + x + 90 = 360

OpenStudy (aum):

Can you solve the above equation for x?

OpenStudy (anonymous):

No I don't. @SethK Is it 150? @aum

OpenStudy (aum):

110 + (x + 10) + x + 90 = 360 2x + 210 = 360 2x = 360 - 210 = 150 x = 150/2 = 75

OpenStudy (anonymous):

So x is 75?

OpenStudy (aum):

Yes. But they want angle K. angle K = x + 10 = 75 + 10 = 85 degrees.

OpenStudy (anonymous):

Oh, well that makes more sense. I've had a hard problem with this question I didn't understand. Now I do. So thank you :)

OpenStudy (aum):

They want you to show each step. So your answer can be: The four angles of a quadrilateral add to 360 degrees. Therefore, angle J + angle K + angle L + angle M = 360 degrees. Substituting for the angles we get: 110 + (x + 10) + x + 90 = 360 2x + 210 = 360 subtract 210: 2x = 360 - 210 2x = 150 divide by 2 x = 150/2 = 75 angle K = x + 10 = 75 + 10 = 85 degrees. You are welcome.

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