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Is the integral of ln(0) an improper integral?
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Since taking the limit of it, you would be approaching \[-\infty\]
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If it helps, I just put ln(0) in my calculator and got a domain error. I don't know anything about integrals though :/
ya, that didn't help. thanks though
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your question, as stated, makes little sense. Try giving us the original question.
\[\int\limits_{1}^{2} \ln(x-1) dx\]
I meant evaluated at ln(1-1)
the integral you typed is an improper integral
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